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2021 Neco Chemistry Practical Specimen Questions
TITRATION
(i) Dilute sodium hydroxide solution
(ii) Dilute ammonia solution
(iii) Dilute hydrochloric acid
(iv) Dilute trinitrate(V)acid
(v) Distilled water
(vi) Red and blue litmus paper
(vii) Barium chloride solution
(viii) Phenolphthalein solution
(ix) Methyl orange
(x) One boiling tube
(xi) Five test tubes
(xii) Source of heat
(xiii) Wash bottle containing distilled water
(xiv) Filtration apparatu
Answers To Neco Practical Chemistry 2021
(1a)
Tabulate
Volume of pipette used=25cm3.
Indicator used= Methyl orange
Under Titration, Rough, 1st, 2nd, 3rd,
Final burette reading; |25.00| |23.40| |23.50| 23.60|
Initial burette reading; |0.00| |0.00| |0.00| |0.00|
Volume of A used; |25.00| |23.40| |23.50| |23.60|
(1ai)
Average volume of Acid used=23.40+23.50+23.60/3 =70.5/3=23.50cm3
(1aii)
This is because it is a reaction between a weak acid and strong base
(1aiii)
A funnel should be used while transferring the acid into the burette.
(1bi)
Conc of A in mol|dm³ =?
Conc of A in g|dm³ = 12.75g|dm³
Molar mass of A, NaHSO⁴ = 23+1+32+64
=120g|dm³
From.
Conc(mol/dm³) = conc(g/dm³)/molar mass
Conc =12.75/120
Conc =0.106mol/dm³
(1bii)
Con of B in mol/dm³ =?
Ca =0.106, Cb =? Va =23.50cm³, Vb =25.00cm³
na=1 , nb=1
From; CaVa/CbVb=na/nb
Cb=CaVanb/Vbna
Cb=0.10623501/25.001
Cb=2.5/25
Cb=0.1mol/dm³
(1biii)
Conc of B in g/dm³=?
Molar mass of B , NaOH=23+16+1=40g/mol
From; conc(g/dm³)=conc(mol/dm³)molar mass
=0.140
=4.0g/dm³
(1biv)
Mass of salt formed =?
Recall mole of NaHSO⁴=?
From; mole =con(mol/dm³)*vol(cm³)/1000
Mole=0.106*23.50/1000
Mole=0.0025mol of NaHSO⁴
By proportion 1mol of NaHSO⁴ produce 1mol of Na²SO⁴ 0.0025mol of NaHSO⁴ will produce X mol of Na²SO⁴ X=0.00251=0.0025mol of NaSO⁴
Molar mass of Na²SO⁴=(232) + 32 + (16*4)
=46+32+64
=142g/mol
Recall; mole =mole/molar mass
Mass =mole * molar mass
Mass =0.0025*142
Mass =0.36g of Na²SO⁴
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