WAEC Chemistry practical specimen Answers 2023 has been solved here.
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2023 WAEC CHEMISTRY PRACTICAL ANSWERS

Burette Readings | Rough | 1st Titration | 2nd Titration | 3rd Titration |
---|---|---|---|---|
Final burette readings (cm³) | 25.60 | 48.10 | 24.60 | 24.80 |
Initial burette readings(cm³) | 1.00 | 23.60 | 0.10 | 0.30 |
Volume of Acid used (cm³) | 24.60 | 24.50 | 24.50 | 24.50 |
Volume of A used = 1st + 2nd + 3rd/3
Average Volume of A used = 24.50+24.50+24.50/3
Average volume of A used = 73.50cm³/3 = 24.50cm3
Write the Equation of the reaction
Na2CO3•xH2O + 2HCl → 2NaCl + H2O + CO2
Mole ratio of base to acid = 1 : 2
500cm3 of Na2CO3 XH2O Contain 5.0g
1000cm3 will contain 5/500 x 100/1 = 12gdm3
therefore Mass Concentrated of Na2CO3 XH2O = 12gdm3

b) Molar Concentration of anhydrous Na2CO3 in solution B
Cb = CaVaNb/VbNa
Cb = 0.086 x 24.50 x 1/25 x 2
Cb = 0.0421m
c) Find the Value of X
Na2CO3•xH2O = 12.0g/dm3
Molar Concentration = 0.0421mol/dm3
Molar Mass = Mass Concentration/Molar Conc.
Molar Mass = 12.0g/dm3/0.042mol/dm3
Molar Mass = 285.7g/mol
Value of X
Na2CO3•xH2O = 285.7g/mol
Na2CO3 = 106g/mol
H20 = 18g/mol
106 + (X *18) = 285.7g/mol
18x = 285.7g/mol – 106g/mol
x = 285.7 – 106/18
x = 179.7/18
x = 9.9 approximately 10 ( since x must be whole number)
Percentage of Water of Crystallization.
Mass of water/Mass of hydrated salt x 100%
= 179.7/285 x 100%
= 62.8%
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110 Comments
I don’t understand what you wrote that 500cm³ of Na2CO3.xH2O contains5.0g
1000cm³contains 12g
Yeah…that doesn’t hold water.
I can’t fix how 12 g/dm3 came about?
U can use total mass of water of crystallization/molmass times 100
Same as me because I know that initial reading is 0.00all through.
Chaii
Bruh,titre value can start anyhow guyyy 😂😂😂
And nah like this you wanna write chemistry practical😓😁
Junior waec
exactly what i got is 10 and the equation they wrote what was the need for them to write X when in the real waec question from my teacher they have already written 10 but they are saying X
I think it’s part of the question
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We are meant to look for mass conc there and you know that it is= mass ÷volume(in dm-3) so there for divide it and multiply by 1000 because the “cm-3” need to be converted to “dm-3
If you want it
What it gets
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me i dont even understand
Are you a student or a teacher?
Thank you
Are dis answers really True??
Nope
Pls I need a reply from someone
Yeah, it’s talky with the practical guide I was given as a subject teacher…and I have also gotten through their solutions..it’s all fine
Plz I need a repl
Plz sir tell us the truth
Can you pls show me how to prepare the solutions and carry out the practical myself?
Sure
They are d likely questions
Just study them
Is there any question given in the entire write up?
Sure
Hi
I need the 2023 waec English answers
Me too pls don’t forget English Oo
I need the 2023 waec mathematics answers and thanks for this one.
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I need 2023 math and English WAEC question and answer
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I don’t understand
Thank you for your good work but we all the subjects please mathematics and English
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thanks for the good work
Show your Conc of acid is gotten
Pls show us how the concentration of the acid is gotten..
Not actually depends on the end point your school is using
Thanks very much sir
Thanks, but I need the main questions for volumetricanalysis
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Are this answers really true ???
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I need English essay and objectives for WAEC 2023
Pls sir is there how you can notify us if anything else is out.
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TO GET THE 2023 WAEC CHEMISTRY PRACTICAL QUESTIONS AND ANSWERS,CALL OR MESSAGE 08024485178 ON WHATSAPP NOW
I need chemistry practical answers for today
Thanks for the good work sir
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What about the salt analysis practical
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Thank u Sir
But sir, why is the mass concentration 12g|dm³ and not 10g|dm³?
Because that is what the questions told us
But sir the value of x suppose to be 7.34
Because 5.0/0.5/1000=5.0/0.5=10g|mol
Nice job sir
The mass concentration of the hydrated salt , that is, Specimen B, is given as 5g/dm3 by WAEC. From where did you get 5g/500cm3, which you converted to 12g/dm3?
From the list of specimens and instructions for Practical Chemistry from WAEC, we can see that 5g of B is to be dissolved in 1 dm3. So the mass concentration of B is 5g/dm3.
From calculations using the instructions from WAEC, the molar concentration of A is 0.10 mol/dm3.
Based on the above data, the volume of acid will be much lower .
I need help
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Thanks
Sir, these are the only questions on chemistry practical
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Please how did they get the molar mass I don’t understand
Thank you very much for your help,pls when is igbo questions coming out the exam is tomorrow
I really appreciate this but we don’t have to depend on this
We have to work harder on our own
Like that one they wrote 12gdm/3
Let assume we didn’t go through the solutions
Some fools are still going to write it like that
So pls guys don’t let us depend on this
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Thanks for the update
Please how can I join the group
OK if we can create a group for interested one’s. I think it will help us .
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Really appreciate you
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How did you get your Na2CO3.xH2O
Like i don’t understand how
How did you get your Na2CO3.xH2O =12
I am interesting add me 08130091770
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How do I join the group
Pls can u explain hw u got 12g/mol
How is Ca = 0.086
I was getting 0.082 and it is really changing my answers
The molar concentration is supposed to be 10 and not 12
That’s true
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Sigh* I wish it was more clearer man😉
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